Find the inverse function f−1(x)f^{-1}(x)f−1(x) of f(x)=4x−2f(x) = 4x - 2f(x)=4x−2.
f−1(x)=x+24f^{-1}(x) = \frac{x+2}{4}f−1(x)=4x+2
f−1(x)=4x+2f^{-1}(x) = 4x + 2f−1(x)=4x+2
f−1(x)=x−24f^{-1}(x) = \frac{x-2}{4}f−1(x)=4x−2
f−1(x)=2−4xf^{-1}(x) = 2 - 4xf−1(x)=2−4x