Find the inverse function f−1(x)f^{-1}(x)f−1(x) for f(x)=\acxx−2f(x) = \ac{x}{x-2}f(x)=\acxx−2 (assume xeq2x eq 2xeq2).
f−1(x)=\ac2xx−1f^{-1}(x) = \ac{2x}{x-1}f−1(x)=\ac2xx−1
f−1(x)=\acx−2xf^{-1}(x) = \ac{x-2}{x}f−1(x)=\acx−2x
f−1(x)=\ac2x−1xf^{-1}(x) = \ac{2x-1}{x}f−1(x)=\ac2x−1x
f−1(x)=\ac2x−1f^{-1}(x) = \ac{2}{x-1}f−1(x)=\ac2x−1