Find the interval of convergence of ∑n=1∞(x−2)nn\displaystyle\sum_{n=1}^{\infty}\frac{(x-2)^n}{n}n=1∑∞n(x−2)n.
1≤x<31 \leq x < 31≤x<3
1<x<31 < x < 31<x<3
1≤x≤31 \leq x \leq 31≤x≤3
−1<x<3-1 < x < 3−1<x<3