Find the interval of convergence for the series ∑n=1∞(−1)n(x−2)nn24n\sum_{n=1}^{\infty} \frac{(-1)^n (x-2)^n}{n^2 4^n}∑n=1∞n24n(−1)n(x−2)n.
(−2,6](-2, 6](−2,6]
[−2,6][-2, 6][−2,6]
(−2,6)(-2, 6)(−2,6)
[2,6)[2, 6)[2,6)