Find the interval of convergence for the power series ∑n=2∞(−1)n(x−3)nnln2n\sum_{n=2}^{\infty} \frac{(-1)^n (x-3)^n}{n \ln^2 n}∑n=2∞nln2n(−1)n(x−3)n.
[2,4][2, 4][2,4]
(2,4)(2, 4)(2,4)
[2,4)[2, 4)[2,4)
(2,4](2, 4](2,4]