Find the interval of convergence for ∑n=1∞(2x−1)nn2\sum_{n=1}^{\infty} \frac{(2x-1)^n}{n^2}∑n=1∞n2(2x−1)n.
(0,1)(0, 1)(0,1)
[0,1][0, 1][0,1]
[0,1)[0, 1)[0,1)
(−1,1)(-1, 1)(−1,1)