Find the integrating factor μ(x)\mu(x)μ(x) for the differential equation y′−6y=e2xy' - 6y = e^{2x}y′−6y=e2x.
μ(x)=e6x\mu(x) = e^{6x}μ(x)=e6x
μ(x)=e−6x\mu(x) = e^{-6x}μ(x)=e−6x
μ(x)=6x\mu(x) = 6xμ(x)=6x
μ(x)=−6x\mu(x) = -6xμ(x)=−6x