Find the integrating factor for the equation xy′+(x+1)y=exx y' + (x+1)y = e^xxy′+(x+1)y=ex.
μ(x)=xex\mu(x) = x e^xμ(x)=xex
μ(x)=ex\mu(x) = e^xμ(x)=ex
μ(x)=x\mu(x) = xμ(x)=x
μ(x)=x2\mu(x) = x^2μ(x)=x2