Find the integer values of xxx satisfying 22x−3⋅2x+1+8≤02^{2x} - 3 \cdot 2^{x+1} + 8 \leq 022x−3⋅2x+1+8≤0.
x=1x = 1x=1
x=2x = 2x=2
x=1,2x = 1, 2x=1,2
x=0,1,2x = 0, 1, 2x=0,1,2