Find the indefinite integral of f(x)=1x2+1f(x) = \frac{1}{x^2+1}f(x)=x2+11.
ln(x2+1)+C\ln(x^2+1) + Cln(x2+1)+C
−1x+1+C\frac{-1}{x+1} + Cx+1−1+C
arctan(x)+C\arctan(x) + Carctan(x)+C
13x3+C\frac{1}{3}x^3 + C31x3+C