Find the indefinite integral ∫1x2dx\int \frac{1}{x^2} dx∫x21dx (for x≠0x \neq 0x=0).
−1x+C-\frac{1}{x} + C−x1+C
1x+C\frac{1}{x} + Cx1+C
ln∣x2∣+C\ln|x^2| + Cln∣x2∣+C
−1x2+C-\frac{1}{x^2} + C−x21+C