Find the general solution to y′−y=exy' - y = e^xy′−y=ex.
y=(x+C)exy = (x+C)e^xy=(x+C)ex
y=x+Cexy = x + Ce^xy=x+Cex
y=Cex−xy = Ce^x - xy=Cex−x
y=(x+C)e−xy = (x+C)e^{-x}y=(x+C)e−x