Find the general solution to y′=11+x2y' = \frac{1}{1+x^2}y′=1+x21.
y=arctan(x)+Cy = \arctan(x) + Cy=arctan(x)+C
y=tan(x)+Cy = \tan(x) + Cy=tan(x)+C
y=ln(1+x2)+Cy = \ln(1+x^2) + Cy=ln(1+x2)+C
y=arcsec(x)+Cy = \text{arcsec}(x) + Cy=arcsec(x)+C