Find the general solution to y′=cos(x)y' = \cos(x)y′=cos(x).
y=sin(x)+Cy = \sin(x) + Cy=sin(x)+C
y=−sin(x)+Cy = -\sin(x) + Cy=−sin(x)+C
y=cos(x)+Cy = \cos(x) + Cy=cos(x)+C
y=−cos(x)+Cy = -\cos(x) + Cy=−cos(x)+C