Find the general solution to y′′−4y=0y'' - 4y = 0y′′−4y=0.
y=c1e2x+c2e−2xy = c_1 e^{2x} + c_2 e^{-2x}y=c1e2x+c2e−2x
y=c1cos2x+c2sin2xy = c_1 \cos 2x + c_2 \sin 2xy=c1cos2x+c2sin2x
y=c1e4x+c2e−4xy = c_1 e^{4x} + c_2 e^{-4x}y=c1e4x+c2e−4x
y=c1+c2e−4xy = c_1 + c_2 e^{-4x}y=c1+c2e−4x