Find the general solution to y′+2y=e−3xy' + 2y = e^{-3x}y′+2y=e−3x.
y=−e−3x+Ce−2xy = -e^{-3x} + Ce^{-2x}y=−e−3x+Ce−2x
y=e−3x+Ce2xy = e^{-3x} + Ce^{2x}y=e−3x+Ce2x
y=−e−2x+Ce−3xy = -e^{-2x} + Ce^{-3x}y=−e−2x+Ce−3x
y=e3x+Ce−2xy = e^{3x} + Ce^{-2x}y=e3x+Ce−2x