Find the general solution to xy′+2y=4x2xy' + 2y = 4x^2xy′+2y=4x2.
y=x2+C/x2y = x^2 + C/x^2y=x2+C/x2
y=x2+C/xy = x^2 + C/xy=x2+C/x
y=x3+C/x2y = x^3 + C/x^2y=x3+C/x2
y=x2+Cy = x^2 + Cy=x2+C