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Differential Equationshard
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Find the general solution to the differential equation z′=zx+3+(zx)2z' = \frac{z}{x} + \sqrt{3 + (\frac{z}{x})^2}z′=xz​+3+(xz​)2​ using the substitution u=zxu = \frac{z}{x}u=xz​.