Find the general solution to the differential equation y′+y=y3y' + y = y^3y′+y=y3.
y−2=1+Ce2xy^{-2} = 1 + Ce^{2x}y−2=1+Ce2x
y2=1+Ce−2xy^2 = 1 + Ce^{-2x}y2=1+Ce−2x
y−2=Ce2x−1y^{-2} = Ce^{2x} - 1y−2=Ce2x−1
y2=Ce2x+1y^2 = Ce^{2x} + 1y2=Ce2x+1