Find the general solution of y′=2xyy' = \frac{2x}{y}y′=y2x.
y2−2x2=Cy^2 - 2x^2 = Cy2−2x2=C
y2=2x2+Cy^2 = 2x^2 + Cy2=2x2+C
y=x2+Cy = x^2 + Cy=x2+C
y2=x2+Cy^2 = x^2 + Cy2=x2+C