Find the general solution of y′=5x4y' = 5x^4y′=5x4.
y=5x5+Cy = 5x^5 + Cy=5x5+C
y=x5+Cy = x^5 + Cy=x5+C
y=15x5+Cy = \frac{1}{5}x^5 + Cy=51x5+C
y=x4+Cy = x^4 + Cy=x4+C