Find the general solution of y′′−4y′+4y=0y'' - 4y' + 4y = 0y′′−4y′+4y=0.
y=(A+Bx)e2xy = (A+Bx)e^{2x}y=(A+Bx)e2x
y=(A+Bx)e−2xy = (A+Bx)e^{-2x}y=(A+Bx)e−2x
y=Ae2x+Be−2xy = Ae^{2x} + Be^{-2x}y=Ae2x+Be−2x
y=Ae2x+Bxe2xy = A e^{2x} + Bx e^{2x}y=Ae2x+Bxe2x