Find the general solution of y′′−4y=0y'' - 4y = 0y′′−4y=0.
y=c1e2x+c2e−2xy = c_1e^{2x} + c_2e^{-2x}y=c1e2x+c2e−2x
y=c1cos(2x)+c2sin(2x)y = c_1\cos(2x) + c_2\sin(2x)y=c1cos(2x)+c2sin(2x)
y=c1e4x+c2e−4xy = c_1e^{4x} + c_2e^{-4x}y=c1e4x+c2e−4x
y=c1ex+c2e−xy = c_1e^x + c_2e^{-x}y=c1ex+c2e−x