Find the general solution of xy′+y=y2xy' + y = y^2xy′+y=y2.
y=11+Cxy = \frac{1}{1 + Cx}y=1+Cx1
y=x1+Cxy = \frac{x}{1 + Cx}y=1+Cxx
y=1x+Cy = \frac{1}{x + C}y=x+C1
y=11−Cxy = \frac{1}{1 - Cx}y=1−Cx1