Find the general solution of the equation y′=xex−yy' = x e^{x-y}y′=xex−y.
ey=xex−ex+Ce^y = x e^x - e^x + Cey=xex−ex+C
ey=ex(x−1)+Ce^y = e^x(x-1) + Cey=ex(x−1)+C
ey=ex(x+1)+Ce^y = e^x(x+1) + Cey=ex(x+1)+C
ey=exx+Ce^y = e^x x + Cey=exx+C