Find the general solution of the differential equation y′=yx+csc(yx)y' = \frac{y}{x} + \csc(\frac{y}{x})y′=xy+csc(xy) using v=y/xv = y/xv=y/x.
−cos(y/x)=ln∣x∣+C-\cos(y/x) = \ln|x| + C−cos(y/x)=ln∣x∣+C
−sin(y/x)=ln∣x∣+C-\sin(y/x) = \ln|x| + C−sin(y/x)=ln∣x∣+C
cos(y/x)=ln∣x∣+C\cos(y/x) = \ln|x| + Ccos(y/x)=ln∣x∣+C
sin(y/x)=ln∣x∣+C\sin(y/x) = \ln|x| + Csin(y/x)=ln∣x∣+C