Find the general solution for y′+2xy=xy' + 2xy = xy′+2xy=x.
y=12+Ce−x2y = \frac{1}{2} + Ce^{-x^2}y=21+Ce−x2
y=1+Ce−xy = 1 + Ce^{-x}y=1+Ce−x
y=x2+Cy = x^2 + Cy=x2+C
y=12x2+Cy = \frac{1}{2}x^2 + Cy=21x2+C