Find the general solution for the separable equation dydx=exy3\frac{dy}{dx} = \frac{e^x}{y^3}dxdy=y3ex for y≠0y \neq 0y=0.
y=(4ex+C)1/4y = (4e^x + C)^{1/4}y=(4ex+C)1/4
y4=4ex+Cy^4 = 4e^x + Cy4=4ex+C
y=ex+C4y = \sqrt[4]{e^x + C}y=4ex+C
y=ln(ex+C)y = \ln(e^x + C)y=ln(ex+C)