Find the general solution for an=5an−1a_n = 5a_{n-1}an=5an−1 given a0=2a_0 = 2a0=2.
an=2⋅5na_n = 2 \cdot 5^nan=2⋅5n
an=5⋅2na_n = 5 \cdot 2^nan=5⋅2n
an=2+5na_n = 2 + 5nan=2+5n
an=2n+5a_n = 2n + 5an=2n+5