Find the first-order partial derivative ∂f∂y\frac{\partial f}{\partial y}∂y∂f for the function f(x,y)=yx2f(x,y) = \frac{y}{x^2}f(x,y)=x2y.
1x2\frac{1}{x^2}x21
−2yx3-\frac{2y}{x^3}−x32y
−1x2-\frac{1}{x^2}−x21
2yx3\frac{2y}{x^3}x32y