Find the excluded values of f(x)=1x2+xf(x) = \dfrac{1}{x^2 + x}f(x)=x2+x1.
x=0x = 0x=0 and x=−1x = -1x=−1
x=0x = 0x=0 only
x=1x = 1x=1 and x=−1x = -1x=−1
x=1x = 1x=1 only