Find the excluded values for 7(x−1)(x+3)\frac{7}{(x-1)(x+3)}(x−1)(x+3)7.
x=1,x=−3x = 1, x = -3x=1,x=−3
x=−1,x=3x = -1, x = 3x=−1,x=3
x=7x = 7x=7
x=0x = 0x=0