Find the equation of the tangent to x2+y2=10x^2 + y^2 = 10x2+y2=10 at (1,3)(1, 3)(1,3).
x+3y=10x + 3y = 10x+3y=10
3x+y=103x + y = 103x+y=10
x−3y=10x - 3y = 10x−3y=10
x+3y=0x + 3y = 0x+3y=0