Find the equation of the tangent to the parabola y2=4xy^2 = 4xy2=4x at the point (1,2)(1, 2)(1,2).
x−y+1=0x - y + 1 = 0x−y+1=0
x+y−3=0x + y - 3 = 0x+y−3=0
x−2y+4=0x - 2y + 4 = 0x−2y+4=0
x−y+3=0x - y + 3 = 0x−y+3=0