Find the equation of the tangent to circle x2+y2=10x^2 + y^2 = 10x2+y2=10 at point (3,1)(3, 1)(3,1).
3x+y=103x + y = 103x+y=10
x+3y=10x + 3y = 10x+3y=10
3x+y=43x + y = 43x+y=4
x−3y=10x - 3y = 10x−3y=10