Find the equation of the tangent plane to the surface x2+2y2+3z2=6x^2 + 2y^2 + 3z^2 = 6x2+2y2+3z2=6 at the point (1,1,1)(1, 1, 1)(1,1,1).
2x+4y+6z=122x + 4y + 6z = 122x+4y+6z=12
x+y+z=3x + y + z = 3x+y+z=3
2x+2y+3z=72x + 2y + 3z = 72x+2y+3z=7
x+2y+3z=6x + 2y + 3z = 6x+2y+3z=6