Find the equation of the normal to the parabola y2=4xy^2 = 4xy2=4x at the point (1,2)(1, 2)(1,2).
x+y=3x + y = 3x+y=3
x−y=−1x - y = -1x−y=−1
y=−x+3y = -x + 3y=−x+3
x+y=1x + y = 1x+y=1