Find the equation of the normal to the circle x2+y2=13x^2 + y^2 = 13x2+y2=13 at the point (2,3)(2, 3)(2,3).
2x+3y=132x + 3y = 132x+3y=13
3x−2y=03x - 2y = 03x−2y=0
3x−2y=133x - 2y = 133x−2y=13
2x+3y=02x + 3y = 02x+3y=0