Find the equation of the line perpendicular to y=2x+1y = 2x + 1y=2x+1 passing through (0,3)(0, 3)(0,3).
y=−12x+3y = -\frac{1}{2}x + 3y=−21x+3
y=2x+3y = 2x + 3y=2x+3
y=12x+3y = \frac{1}{2}x + 3y=21x+3
y=−2x+3y = -2x + 3y=−2x+3