Find the equation of the chord of the circle x2+y2=25x^2+y^2=25x2+y2=25 that is bisected at (2,1)(2, 1)(2,1).
2x+y−5=02x+y-5=02x+y−5=0
x+2y−5=0x+2y-5=0x+2y−5=0
2x+y−4=02x+y-4=02x+y−4=0
x+y−3=0x+y-3=0x+y−3=0