Find the equation of a tangent to the circle x2+y2=13x^2 + y^2 = 13x2+y2=13 at the point (2,3)(2, 3)(2,3).
2x+3y=132x + 3y = 132x+3y=13
3x+2y=123x + 2y = 123x+2y=12
2x−3y=132x - 3y = 132x−3y=13
x+y=5x + y = 5x+y=5