Find the equation of a line that is perpendicular to the line 4x−3y+7=04x - 3y + 7 = 04x−3y+7=0.
4x+3y=c4x + 3y = c4x+3y=c
3x+4y=c3x + 4y = c3x+4y=c
3x−4y=c3x - 4y = c3x−4y=c
4x−3y=c4x - 3y = c4x−3y=c