Find the eigenvectors of A=(3113)A = \begin{pmatrix}3 & 1 \\ 1 & 3\end{pmatrix}A=(3113) corresponding to λ=4\lambda = 4λ=4.
c(11)c\begin{pmatrix}1\\1\end{pmatrix}c(11), c≠0c\neq 0c=0
c(1−1)c\begin{pmatrix}1\\-1\end{pmatrix}c(1−1), c≠0c\neq 0c=0
c(40)c\begin{pmatrix}4\\0\end{pmatrix}c(40), c≠0c\neq 0c=0
c(01)c\begin{pmatrix}0\\1\end{pmatrix}c(01), c≠0c\neq 0c=0