Find the eigenvalues of A=(3113)A = \begin{pmatrix}3 & 1 \\ 1 & 3\end{pmatrix}A=(3113).
λ=2\lambda = 2λ=2 and λ=4\lambda = 4λ=4
λ=3\lambda = 3λ=3 and λ=3\lambda = 3λ=3
λ=1\lambda = 1λ=1 and λ=5\lambda = 5λ=5
λ=0\lambda = 0λ=0 and λ=6\lambda = 6λ=6