Find the domain of f(x)=sin(x)f(x) = \sqrt{\sin(x)}f(x)=sin(x).
[0,π][0, \pi][0,π]
[2kπ,(2k+1)π][2k\pi, (2k+1)\pi][2kπ,(2k+1)π] for k∈Zk \in \mathbb{Z}k∈Z
[0,2π][0, 2\pi][0,2π]
[kπ,2kπ][k\pi, 2k\pi][kπ,2kπ]