Find the directional derivative of f(x,y)=x2yf(x, y) = x^2 yf(x,y)=x2y at (1,2)(1, 2)(1,2) in the direction of v⃗=⟨3,4⟩\vec{v} = \langle 3, 4 \ranglev=⟨3,4⟩.
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