Find the derivative of y=12x4−3xy = \frac{1}{2}x^4 - 3\sqrt{x}y=21x4−3x.
2x3−32x2x^3 - \frac{3}{2\sqrt{x}}2x3−2x3
2x3−32x−1/22x^3 - \frac{3}{2}x^{-1/2}2x3−23x−1/2
4x3−12x4x^3 - \frac{1}{2\sqrt{x}}4x3−2x1
Both a and b are correct