Find the derivative of f(z)=ln(e2z+1)f(z) = \ln(e^{2z} + 1)f(z)=ln(e2z+1).
2e2ze2z+1\frac{2e^{2z}}{e^{2z} + 1}e2z+12e2z
e2ze2z+1\frac{e^{2z}}{e^{2z} + 1}e2z+1e2z
2e2z2e^{2z}2e2z
1e2z+1\frac{1}{e^{2z} + 1}e2z+11