Find the derivative of f(x)=xxf(x) = x^xf(x)=xx.
xxlnxx^x \ln xxxlnx
xx(1+lnx)x^x(1 + \ln x)xx(1+lnx)
x⋅xx−1x \cdot x^{x-1}x⋅xx−1
xxln(xx)x^x \ln(x^x)xxln(xx)