Find the derivative of f(x)=sin(x3)+cos3(x)f(x) = \sin(x^3) + \cos^3(x)f(x)=sin(x3)+cos3(x).
3x2cos(x3)−3cos2(x)sin(x)3x^2 \cos(x^3) - 3 \cos^2(x) \sin(x)3x2cos(x3)−3cos2(x)sin(x)
3x2cos(x3)+3cos2(x)sin(x)3x^2 \cos(x^3) + 3 \cos^2(x) \sin(x)3x2cos(x3)+3cos2(x)sin(x)
3x2cos(x3)−3cos2(x)3x^2 \cos(x^3) - 3 \cos^2(x)3x2cos(x3)−3cos2(x)
cos(x3)−3cos2(x)sin(x)\cos(x^3) - 3 \cos^2(x) \sin(x)cos(x3)−3cos2(x)sin(x)